I'm confused. . .454CC = .28CI
This is what I had thought these engines were:
traxxas 2.5=.18
traxxas 3.3=.20
O.S. 3.4=.21
mach 426=.26
mach 427=.26
mach 454=.28
Anyone wanna help me figure this out?
Thanks.
Mach .26 w/PS SG = 4.26 cc displacement
Mach .28 with PS SG = 4.57 cc displacement
Losi 454 Engine,
Overview
The Losi 454 engine is a potent .28-sized performance engine. Specifically built for 1/8-scale off-road vehicles, the 454 engine offers a large cooling head for cooler and more reliable operation.
The large-bore carburetor design provides ample intake capacity, creating the kind of powerful throttle response and acceleration you want for any track or terrain. Additionally, fine-tuning the 454 for any temperature or weather condition is simple thanks to the easy-to-adjust high- and low-speed needles.
Specs
- Displacement:.28 cu in
- Bore:0.728 in (18.50mm)
- Stroke:0.669 in (17.00mm)
- Engine (Only) Weight:0.859 lb (390 g)
- RPM Range:36,000
- # of Ports:8
- Carb Type:Two-Needle Slide Aluminum/Steel
- Crank Type:High-Carbon Steel, Precision ground and polished with "Turbo Grooves"[/list]
The mathematical formula for figuring out any piston engine's size is bore x bore x stroke x number of cylinders x .7854 (.7854 = pi divided by 4). Plug in the numbers for the 454 that Sugafree gave and you have .728 x .728 x .669 x 1 x .7854 = .278. Round it off and you have .28. Convert .278 to cubic centimeters and you get 4.555. 454 just sounds better though.
Thanks to both of you.