Sport_Pilot
Posts: 7405
Joined: 1/21/2002 From: Acworth,
GA, USA Status: offline
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quote:
ORIGINAL: DarZeelon quote:
ORIGINAL: Red B. Efficiency = (propeller thrust * velocity) / engine power With this definition, as airspeed approaches zero so does efficiency. At zero airspeed the propeller may provide a lot of thrust, but because it produces no useful work (moving the aircraft forward) all the energy output of the engine is wasted and thus efficiency is zero. Red, I was never saying propeller efficiency is a function of speed; just that it is stated at a speed. Prop-fans of current designs reach their optimal efficiency of just over 80%, when they are traveling at a forward speed of 0.8 Mach... The advance angle, on which the efficiency is dependent, is not stated - just the speed. Also, because engine power output at 100% efficiency can be stated as calculated force * velocity and dividing the actual thrust * velocity by this number would equal efficiency, what you wrote and what I wrote are exactly the same thing. Because the velocity is the same below and above the dividing line, one could just divide the actual thrust by the calculated thrust and get the same ratio. And it is true. When the plane is stationary, efficiency is indeed zero... you cannot calculate thrust from HP at zero speed. The calcuated thrust would then be infinity; and when any finite number is divided by infinity, the result is zero. Thrust is dependent on the diameter of the prop and on its advance angle... One of the reasons a helicopter rotor makes more thrust than a propeller, using the same amount of HP... I think velocity is actually delta velocity, the differance in the velocity of the air going into the prop and leaving the prop. For a static run on the ground the velocity is the same as the prop wash velocity, but in the air it is the propwash velocity minus the aircraft velocity.
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