Servo Torque question?
06-09-2004, 06:57 PM
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Servo Torque question?
Another thread got me wondering about servo torque. Say brand "X" servo has 50 oz/in of torque, I would guess that is at the point on the arm that is 1" from the output shaft.
Question is, will the torque double at a point 1/2" from shaft, & be cut in half at 2" from the shaft? Is it linear or does it need to be calculated with some formula?
Question is, will the torque double at a point 1/2" from shaft, & be cut in half at 2" from the shaft? Is it linear or does it need to be calculated with some formula?
06-09-2004, 09:31 PM
#3
RE: Servo Torque question?
ORIGINAL: TLH101
Another thread got me wondering about servo torque. Say brand "X" servo has 50 oz/in of torque, I would guess that is at the point on the arm that is 1" from the output shaft.
Question is, will the torque double at a point 1/2" from shaft, & be cut in half at 2" from the shaft? Is it linear or does it need to be calculated with some formula?
Another thread got me wondering about servo torque. Say brand "X" servo has 50 oz/in of torque, I would guess that is at the point on the arm that is 1" from the output shaft.
Question is, will the torque double at a point 1/2" from shaft, & be cut in half at 2" from the shaft? Is it linear or does it need to be calculated with some formula?
The force generated at the end of the servo arm of various lengths is:
Force = Torque/distance
Force at 1 inch = 50/1 = 50 ounces
Force ar 1/2 inch = 50/.5 = 100 ounces
Force ar 2 inches = 50/2 = 25 ounces
The torque is always the same for any servo, it just generates different forces depending which hole you use on the servo arm. The more force it generates, the slower the control surface moves. The less force it generates, the faster the control surface moves. I haven't even gotten into the control horn distance. That's another question/topic.
