I need fuel with 7% oil by volume.
I have Powermaster 15% Sport fuel, which is 18% oil by volume.
My math is as follows:
128 oz of fuel =
86 oz of methanol
23 oz of oil
19 oz of nitromethane
If I take 16 oz of the fuel, I have:
10.725 oz of methanol
2.875 oz of oil
2.4 oz of nitromethane
The above is still 18% oil by volume.
Now, by my calculations, if I add 30 oz of pure methanol to the 16 oz of this Powermaster fuel, I will have:
46 oz of 7% oil by volume, fuel.
Which would be:
40.725 oz of methanol
2.875 oz of oil
2.4 oz of nitromethane
Anyone see anything wrong with my math?
Thanks!











