Quote:

ORIGINAL: Kmot

I need fuel with 7% oil by volume.

I have Powermaster 15% Sport fuel, which is 18% oil by volume.

My math is as follows:

128 oz of fuel =

86 oz of methanol

23 oz of oil

19 oz of nitromethane

If I take 16 oz of the fuel, I have:

10.725 oz of methanol

2.875 oz of oil

2.4 oz of nitromethane

The above is still 18% oil by volume.

Now, by my calculations, if I add 30 oz of pure methanol to the 16 oz of this Powermaster fuel, I will have:

46 oz of 7% oil by volume, fuel.

Which would be:

40.725 oz of methanol

2.875 oz of oil

2.4 oz of nitromethane

Anyone see anything wrong with my math?

Thanks! :)

You have 88.5% methanol, 6.25% oil, 5.2% nitromethane. in 46oz of mixed fuel, you would need 3.22oz of oil to have 7%. I would just subtract the small amount of methanol to bring the oil up. If you dropped the methanol by 6oz to 34.725, you would have 86.8% methanol, 7.2% oil, 6% nitromethane which gives you 40oz of mixed fuel instead of 46oz.