The figures you quote don't add up only because you are changing your point of reference for speed.<div>
</div><div>If you are starting from the left at 20kts in a 20kt wind then your ground speed will be 40kts.</div><div>So your square loop, to remain at constant  visual speed from the ground would need to be </div><div>
</div><div>from left 20kts IAS (40 kts ground speed) </div><div>up accelerate to 40kts IAS</div><div>from right at top accelerate to 60kts IAS (40kts ground speed</div><div>down decelerate to 40kts IAS</div><div>level exit decelrate to 20kts IAS (40kts ground speed)</div><div>
</div><div>and that should add up right.</div><div>
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