Simple question here:

Built a plane that has a weight of 6 lbs. even (weighed with electronic fish scale) and has a wing surface area of 720 sq. in (12 in. chord by 60 in. length). Now the ailerons are 2 in. in width. Should the chord be 14 in. ? Do you figure in the ailerons when figuring the wing loading ?

Thanks

Cary

yes

R8893 is absolutely correct. The ailerons are always included in the wing area, as is the portion of the wing that's covered by the fuselage.<div>
</div><div>  Also, in case you don't have this, a convenient equation you can use, to find wing loading in ounces per square foot, is,</div><div>
</div><div>   wing loading = 2304 times (airplane weight in pounds divided by wing area in square inches) = ounces/sq. ft.</div><div>
</div><div>So, for your plane, WL = 2304 x (6/840) = 16.46 oz/sq ft</div><div>
</div><div>It may be a little sensitive to wind gusts, but should fly great.</div><div>
</div><div>Best of luck</div>

Think your calcs are a bit off as wing loading is weight of model in ounces divided by the wing area in sq. ft which in this case is 6.0 x 16 = 96 divided by (60"x12") 144 = 5 sq.ft. = 19.20 ozs. per sq.ft

Karol

The area of the wing is 14x60=840 sq inches divided by (144 in/sq ft) that gave me the 5.833 sq ft for the wing area.
With that figure of 5.833 sq ft for the wing area and with a weight of 6 lbs (96oz) that calculates out to 16.45 oz per square ft for the wing loading.
Good weight for a 40 size plane...

Thanks guys for the information on figuring wing loading. The plane (SPAD corostang) is a real floater and pleasant to fly with a 55 AX turning a 12 x 4 with mac's black muffler.

Oh boy, I missed that the 2" wide aileron was omitted from that 12" wing chord dimension

Karol