RCU Forums - engine question

Take the wing area in inches and divide by 144 to give you square feet. Take the weight in pounds and multiply by 16 to give you ounces. Now divide the ounces by the square feet to give you ounces per square foot wing loading. One other thing that I have humored myself with over the years is that many, many, many people do not realize that a plane flies on the wing and not the engine. I have over 25 yrs of modeling experience and I just laugh at some of the power requirements that people talk about. Real planes don't take off in 2 feet and stand on the tail vertically. If you are a 3D flier, then that is what you need, but not for scale flight. If the numbers that are posted for the 2300 are correct at 9000 rpm with an 18-6 prop., you are looking at around 15 to 17 pounds of thrust. If the plane weighs 14 pounds, you are looking at better than a 1 to 1 thrust ratio. Why in the world would that not work? Most real planes don't have that and they are not considered marginal. Just some ideas.

John