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Old 01-23-2011 | 11:51 AM
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olnico
 
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Default RE: derjet vampire

ORIGINAL: fougamagister

Hi Oli,

many thanks for your appreciation.

Depends from the type ol Led that you use.

In this case, the led is certified for 45 mA of current absorbtion. You apply the 1st Ohm law : R (resistence) = V(volt) : I (ampere )

This led is certified for 45 mA, your power supply is 7,2 Volt = 7,2 : 0,045 = 160 Ohm. This is the value of resistor

If the power supply will by 11,1 V ( 3Li-Po in Serial config ) = 11,1: 0,045 = 246 Ohm ( Commercial value of 220 or 270 is good.)


Regards


Luciano
www.flyunitedteam.net

Thanks Luciano.
My problem is that, sadly, I lost the track of my LED characteristics. They are old Luxeon 1W @ 3,6V type.
From a rough guess, P=UxI so in that case I = 1/3,6 = 270 mA ?
Which would mean that I'd need a resistor of 27 Ohm @ 7,2V ?
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