[QUOTE]Originally posted by rbshirley
[B]Does anyone remember or know the mathematical formula for determining the amount of oil that needs to be added to increase the percentage of lubrication in a gallon of methanol/oil/nitro mix ?

Just 2 cents....

If I'm not mistaken....18% oil content = 28oz to the gallon,
so many ounces of nitro and so many ounces of methanol to get a certan percentage fuel mix....for a gallon even.
Like 18%oil, 15% nitro...
IF you add more oil to make the mix a lil stiffer it has thrown out the percentages of the other two ingredients (methanol and notro)...and it is now something of a mix...you now have over a gallon of mix..the nitro % has stayed the same the methanol % has stayed the same...but is now out of proportion...
Actually the more oil you add and want to have a "gallon" the less ounces of methanol you add...the ounces of nitro stays the same...
In theory you have to add a little more nitro and a little more methanol in the right ounces to equal the offset for you adding more oil...

Ckeck the mixing chart for model engines at the Klotz WEB sight..
I think you just might want to D/L it and look at the ratios..