RE: Who can help with THIS one? Guru needed :) WILL PAY
What you are dealing with is torque around the CG. Torque can be expressed in inch x ounces. To get your CG where you want it, you need the same number of inch x oz on either side. Say you put your 16 oz 15 inches in front of your desired CG. That's 240 inch x oz. If you can take 240 inch x oz off the back, you won't need any nose weight. Just an example to show how it works.