ORIGINAL: essyou35
''A level 45 degree turn has a loading of 1.41 G's, or a level 60 degree turn - 2 G's''
G force is a function of speed and turn radius, not bank angle. I can make a turn banked at 45 degrees and have 1 G or 9 Gs depending speed. A change in direction is an acceleration, and that is then divided by 9.8 to get the factor of normal gravity you feel.
To get turn radius, you need either degrees per second and speed, RPM, or the arc length of the turn.
I seem to remember another thread with an almost identical statement made in an almost identical fashion, with the poster failing to understand the bank angle to G force relationship expressed by the OP is a simplified case assuming ALL the lift is provided by the wing.
I think we all understand that the acceleration in a turn is a simple velocity squared divided by the radius, and that if the wing is the only source of the force to maintain a constant altitude during the turn then then it'd feel the forces described by the OP.
Now if people want to use the fuse to generate lift, like I do in a rolling circle then all bets are off for any given bank angle and the only relevent items are speed and radius.
Tip stall?? Pretty much what it says really, one wing stalls before the other and back in the day with poorly designed airplanes and airfoils it usually started at the tip first. Don't forget, simply rolling the airplane back to level from banked causes a large angle of attack increase at the tip of the downgoing wing which may already be close to the critical angle of attack.
Cheers