RCU Forums - View Single Post - Negative Gs at the top of loops
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Old 08-16-2014 | 03:45 PM
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drac1
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From: Romaine, Tasmania, AUSTRALIA
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Originally Posted by Jetdesign
There is a lot of 'stuff' in this thread. I think the best thing to do is to keep it simple - trim your plane well, watch wings level, and use power appropriately.

The stuff about gravitational forces and changes in direction may contain a few myths, to put it nicely. G forces have no impact on wings or airfoils generating lift. Momentum will always force the airplane in a straight line in the direction of it's current travel. If your inside wing is down, you will loop inward. If you keep the plane in that attitude (meaning inside wing is now high over top of loop) it will continue on an inward path as long as you are on the elevator. As you're flying over the top with the inside wing still 'down' relative to the airplane (up in your frame of reference), it will still fly in, if you are on the elevator. If you stop driving the plane with elevator and let the wings generate 'lift' (negative lift in this case, toward the bottom of the airplane, or up in your frame of reference), it will force the airplane to start flying out, because the inboard wing is aimed toward the sky, therefore the bottom of the airplane is aimed 'out' and lift toward the bottom of the airplane is therefore 'out'. As soon as you get back on the elevator the plane starts flying back in again because the canopy is aimed toward you.

If you still have trouble with the direction the airplane wants to travel in this situation, practice your knife edge and rolls, and try some point rolls if you can with only elevator inputs. You will get a feel for all of this. Up elevator is always toward the canopy, down always toward the gear. The wings basically follow the path of the nose (for all intents and purposes of this discussion).

If you do get off the elevator just before the top of the loop and start on a slight climb while inverted, yes, you will generate negative G's on the airplane. But that is a result of the change in direction (away from the center of the loop), not a cause.
Hmm. All this is what I have already said earlier.

Lift doesn't make the plane climb, angle of attack on the wing does. The plane needs positive incidence to climb. Letting the elevator off at the top while inverted, will not make the plane fly out as the positive incidence is still making the plane pull towards the canopy, which because it's inverted, will make the plane continue on the arc of the loop (down in your reference). For the plane to fly outwards the incidence of the wing would have to change to negative.

Lift doesn't change from positive to negative (in relation to the model) just because the plane is inverted. The positive incidence is still acting the same relative to the model.