So what your saying is if you give the rudder full deflection in the air and with a 4.8 volt pack and a 6 volt pack its going to pull the same amps? It wont, the 6 volt pack will provide more current which = shorter run time.
Its the same thing as on an electric plane, if you run a 8 cell pack and say a 10" prop and it draws say 10 amps, now take the same setup and put a 9 cell pack on it and it will draw more amps, = shorter run time but more power.
ORIGINAL: STG
ORIGINAL: Iflyit
A 6 volt pack will provide more current draw than a 4.8 that is why it will drain faster.
ORIGINAL: STG
ORIGINAL: cstevec
Keep in mind too, a 5 cell pack drains faster then a 4 cell pack does so if 4.8 volts will do ya your packs will last longer.
Theoretically that is true if you just turned on your receiver and servos and did not ask any real work out of them. But in the real world what drives these servos is watts (volts x amps = watts) and what really pulls power from the battery is when you put a load on the servos.(fly them around aggressively -- KE puts a lot of work on rudder servo )
4.8volt battery pack x 1400mah = 6,720wh
6.0volt x 1400mah = 8,400wh
As you can see the 6 volt battery carries another cell and so another 1680wh of energy.
Now, if you placed both the batteries under the same load condition so they draw the same amount of watts (flew exactly the same flights--remember it is the watts that drives the servos) do you still think that the 4.8 volt battery with 1680wh less of energy will outlast the 6 volt battery?
It will only draw as much current(watts) as it need in order to get the work(watts) done. Yes at rest the 6.0 V is drawing more, but when working they are drawing only enough to accomplish the task(same).