ORIGINAL: Fishmasterdan
I am thinking 5 ounces gas 5 ounces metanol 1 ounce 35% nitro/castor for a test.
That should be plenty of nitro and oil.
What kind of engine. The math is: 5 oz gas, 5 oz methanol, 0.35oz nitro, 0.65oz oil. = total 11 oz of fuel tha has:
5/11 = 45.5% gas,
5/11 = 45.5% methanol,
0.35/11 = 3.1% nitro
0.65/11 = 5.9% oil (like 1:17 oil: fuel mix)
if you are using gas conversion (with needle bearings on rod) you may reduce the oil content to 1/2. It would be:
10 oz gasoline, 10 oz methanol, 1 oz oil/nitro. This will result:
47.6% gas
47.6% methanol
1.7% nitro
3.1% oil (like 1:32 oil: fuel mix)
RysiuM