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Old 07-08-2007 | 05:36 AM
  #890  
merugo
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From: rome, ITALY
Default RE: Substitute for Ether

Greg, some differences ever arise between theory and practice.
Here this means that in case of a four strokes open crankase fueled vith kerosene trough a carburetor, kerosene cannot evaporate entirely in the combustion chamber. Furthemore, during aspiration its temperature it NEVER can reach the boiling temperature, so the oil remains embedded in kero.
In fact for evaporating in this cycle it should require a MASS heath transfer of such an entity sincerely difficult of conceive. Mix is adiabathically heaten until burning only during the compression phase, but this does not involve any mass heath transfer. So for the entire aspiration phase you are washing your liner with something tha is so viscous as water.
Note that if you dilute 1 part of oil ,say of 200 centistokes, in 9 parts of kerosene, say at 40°C , the resulting viscosity of your mixture will be 3 (THREE) centistokes, a real mess, I guess. And the viscosity lowers until kero starts "boiling" ,that is 180°C.
Passing to two strokes the situation is worse. Its rotating parts are ever under the boiling temperature of kero. This means that if you use the usual 1/3 mix you will have your oil diluted at 50%, this means that your original (mineral) oil, say of 200 centistokes works at a viscosity as reduced as 12 (TWELVE) centistokes, barely sufficient to run bearings.
But if you use no ether mix substituting ether with kerosene , your actual viscosity will go down to less than 7 (SEVEN) centistokes. Draw your conclusions.
As for those team racers going down to less than 10%oil, remember, NONE IS RUNNING WITOUT ETHER, on the contrary, they often use as much as 40% of it, so the useful viscosity is not impaired.
As for Treven, if he runs on his mix No1 at http://www.rcuniverse.com/forum/m_6053759/tm.htm, he works with 22% of its "oil" on which I cannot argue.
Ugo