RCU Forums - View Single Post - control surface torque
View Single Post
Old 07-27-2007 | 09:15 PM
  #2  
wellss
 
Joined: Jun 2002
Posts: 147
Likes: 0
Received 0 Likes on 0 Posts
From: St. Catharines, ON, CANADA
Default RE: control surface torque

If that 50 mph is airspeed, then

force (oz) = sin(angle) * area (sq in) * mph^2 / 560

hinge moment = 25% of surface chord, or 0.5 inches in your example

Torque = force * moment

So, say for 15 degrees of deflection,

Torque = 6 oz-in

If you move the hinge line back from the leading edge, you can reduce the amount of torque needed