I'm not sure I understand your point. Are you a physics expert? There clearly IS such a thing as centrifugal force in modern physics. To alieviate my inability to word this problem in simple English, I submit the following taken from the Natescape page cited at the beginning of this thread:

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The forces that act on a seesaw are 'moments.' Moment is equal to the product of mass and distance (radius) from the center of rotation:

moment = M x R

The forces that act on a rotating rotor head are centrifugal forces. (some prefer to use the term centripetal, which is a bit more to the point but boils down to effectively same thing). This force is equal to the product of the mass and the square of velocity, divided by the radius of the center of mass:

centri{fugal|petal} force: M x V x V / R

Velocity is distance over time, and in this case distance is the product of two, pi, and radius.

velocity = 2 x pi x R / T

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The question then is - can the equation for centrixxxx force be reduced to the equation for moment? The answer is yes. I'm now kicking myself for throwing away the proof, but I do have a counterexample below. Consider a 10 gram blade with a CG 1 centimeter from the root, and a 1 gram blade with a CG 10 centimeters from the root. It's trivial to prove that their moments are the same: 10 x 1 is equal to 1 x 10. But will they exert the same centrifugal force on the rotor head?


F = M x V x V / R

F = M x (D/T) x (D/T) / R

F = M x (2 x pi x R / T) x (2 x pi x R / T) / R

so now we substitute real numbers into each equation...
T has been set to 1 for simplicity.

blade 1: m = 10 grams, r = 1 centimeter, v = 2 x pi x 1
blade 2: m = 1 gram, r = 10 centimeters, v = 2 x pi x 10

F1 = 10g x (2 x pi x 1) x (2 x pi x 1) / 1
F2 = 1g x (2 x pi x 10) x (2 x pi x 10) / 10

divide by (2 x pi) x (2 x pi) to get:

F1 = 10g x 1 x 1 / 1
F2 = 1g x 10 x 10 / 10

multiply to get:

F1 = 10g x 1 / 1cm
F2 = 1g x 100 / 10cm

divide to get:

F1 = 10g / 1cm (note that this looks a lot like the equation for moment)
F2 = 100g / 10cm (that is definitely not a coincidence, I assure you!)

reduce the fraction in the second equation to get:

F1 = 10g / 1cm
F2 = 10g / 1cm

and note that:

F1 = F2

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Seems like sound reasoning to me