What?! More?! Geez...
I guess teachers nowadays teach whatever synthetic division? (I never heard of that before..) ha!
I guess it just means you try some #s to see if you get it to be 0.. something like that.. someone needs to teach me that.. ha! (Let me Google it.. !)
Anyway, this might be hard to see, kind of like magic.....
x^4 - 8x^3 + 13x^2 + 32x - 68
= x^2 (x^2 -8x + 12) + x^2 + 32x - 68
= x^2 ( x-6) (x-2) + (x+34) (x-2)
= (x-2) (x^3 - 6x^2 + x + 34)
= (x-2) [x^3 +2x^2 - 8x^2 + x + 34]
= (x-2) [x^2(x+2) - (8x-17)(x+2)]
= (x-2) (x+2) (x^2 -8x + 17)
= (x-2)(x+2)(x -(4+i))(x -(4-i)) (u guys learned complex #s yet?)
ORIGINAL: NitroVenom
lol well I figuresd it out today, kinda..
I have another ? tho.
Find all the zero's of the function.
f(x) = x^4 -8x^3 +13x^2 +32x -68