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Old 02-01-2010 | 05:28 PM
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dknovick
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Default RE: More voltage or current?


ORIGINAL: Toguro

Can choosing a 7.4 lipoly with a large discharge rate be equivalent to running an 11.1 lipoly with a lower discharge rate? From what little I know about motors, Ni (turns*current) determines how much flux is produced. From this I am assuming that opting for the low voltage/high discharge battery can result in similar performance while reducing wear from arching. Please correct me if I'm incorrect.
Sort of. The magnetic field _is_ proportional to the number of turns * current.

However, the battery is a voltage source (which can supply a maximum current). The current running through the motor is based in the voltage of the battery, the resistance in the wire, the induction in the wire and a few other things (V = IR or I = V/R).

The battery will only provide up to the maximum current. The circuit requires a certain amount of current, and the battery supplies it. It will not "push out" more current. So a lower voltage will generate a lower current (and not a higher current, which is what you would want for this to work).

-Dave