Need Formula to determine pull
#1
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From: Oberlin,
OH
I remember reading the other day someplace where there was a formula to let you know how hard an airplane would pull. It was something like weight times speed times line length or something. If anyone can give me help with this it would be appreciated.
THANKS
THANKS
#2

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Bill.
The formula from Newtonian physics for a mass swinging around on a string is F=Mv^2/r where F is force in pounds, M is mass in slugs, v is velocity in feet per second, and r is the radius in feet. To convert weight in pounds to slugs divide by 32.2 feet per second squared. As an example consider a sport model at 3 pounds going 60 mph on 60 foot lines: A useful conversion factor is that 60mph equals 88 feet per second. 3# divided by 32.2 is 0.093 slugs. So force = 0.093x88x88/60=12# of force. This calculation does not consider any of the aerodynamic forces such as engine offset or rudder offset on the model. Note that the pull increases with the square of the speed; twice as fast is 4 times the pull.
Chuck
The formula from Newtonian physics for a mass swinging around on a string is F=Mv^2/r where F is force in pounds, M is mass in slugs, v is velocity in feet per second, and r is the radius in feet. To convert weight in pounds to slugs divide by 32.2 feet per second squared. As an example consider a sport model at 3 pounds going 60 mph on 60 foot lines: A useful conversion factor is that 60mph equals 88 feet per second. 3# divided by 32.2 is 0.093 slugs. So force = 0.093x88x88/60=12# of force. This calculation does not consider any of the aerodynamic forces such as engine offset or rudder offset on the model. Note that the pull increases with the square of the speed; twice as fast is 4 times the pull.
Chuck



