Scale weight conversion?
#1
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From: Gothenburg, SWEDEN
Do you know how to convert a Tiger at 57 tons to the right weigt for 1/16.
My theory is to use volume. The model is 16 times smaller in each direction.
Therefore you have to divide the real tanks 57 tons with 16 square (57000/(16*16*16) = 13.9 kg.
Im I right?
Martin
My theory is to use volume. The model is 16 times smaller in each direction.
Therefore you have to divide the real tanks 57 tons with 16 square (57000/(16*16*16) = 13.9 kg.
Im I right?
Martin
#3
If you want to weight down your 1;16 Tiger to the actual scale weight, you would want to look for something other than en electric motor to run it. With the Maybach V-12 HL 230 at 700 HP, the Tiger was still underpowered and suffered many problems because of it. Our Pershing had the same problems.
Bill
Bill
#4
16 cubed is the right calculation for mass. To power a 30 lb Tiger would be better accomplished with 12V power and larger motors.
Not to mention the overhaul of running gear, gearbox and hull to withstand the weight increase.
The tank has a difficult enough time with just 2lbs of added metal track!
Not to mention the overhaul of running gear, gearbox and hull to withstand the weight increase.
The tank has a difficult enough time with just 2lbs of added metal track!
#6
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From: Energy Capital,
SK, CANADA
I often wondered why the weight didn't come to scale, then when ppl talk about 30 pounds etc i can see why. how would even shove 30 lbs into that tank? you could make it out of die cast or real metal i suppose....
#7
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From: Gothenburg, SWEDEN
Hi
I´ve not intent to realize this but was interested to find out if the theory is correct...
...maybe less than 7 kg in a T34 is more realstic?
Martin
I´ve not intent to realize this but was interested to find out if the theory is correct...
...maybe less than 7 kg in a T34 is more realstic?
Martin
#8
You could join the MVPA and get a 1;1 scale tank. There you have the actual weight. Tigers are hard to come by but some Movie repros are available.
Bill
Bill
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From: San Paolo Solbrito, ITALY
The problem is that when working in scale not all the physical characteristics do scale in the same way. It's a common problem when making tests on scale models for research or design purposes.
But if we talk about size, your evaluation of the weight going with the square of the linear dimensions is right, since weight is proportional to volume x mass density, and the latter can be assumed as a constant value in our case.
But the base assumption is that you cannot have a full scale model, meaning you cannot have a 1/16 size model, with scale weight, scale power, scale speed and accelleration, scale air drag and ground friction, etc., at the same time.
Weight, size, speed and accelleration can be obtained at the same time, however.
But if we talk about size, your evaluation of the weight going with the square of the linear dimensions is right, since weight is proportional to volume x mass density, and the latter can be assumed as a constant value in our case.
But the base assumption is that you cannot have a full scale model, meaning you cannot have a 1/16 size model, with scale weight, scale power, scale speed and accelleration, scale air drag and ground friction, etc., at the same time.
Weight, size, speed and accelleration can be obtained at the same time, however.
#10
Senior Member
Hey Bill, how much ($$$) do 1:1 Stuarts sell for? There's one at a closed restaurant down the road from me. They used to move it around but I doubt that it runs.




