Originally Posted by
stephensackro
... The motor is a Kv=1000rpm/volt motor. ...
... If I went to a 800 watt Kv=1000rpm/volt motor, would I get about the same rpm since both motors are 1000rpm/volt motors? ...
RPM, current and power would be slightly higher because the copperwire resistance in the bigger motor is lower, which leads to lower voltage losses in the motor.
Efficiency of a bigger motor is slightly higher because of aforementioned lower resistance
and because the motor will operate closer to point of maximum efficiency.
Velocity_konstant_Kv of the new motor should not differ too much though, because both current and power
drawn are proportional to Kv cubed, a very disproportional effect. Unless the power system can handle the increase of course.
E.g. a
05-10-15-20-25% difference in Kv would lead to a
15-30-50-70-95% difference in current and power
drawn.
More expensive

silly, realistic and hopefully instructive
examples of risky changes in voltage (power of 2), pitch and prop-diameter (power of 4!)
Vriendelijke groeten

Ron
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