ORIGINAL: coronabob
My understanding of capacitive discharge ignition is that the muliplication of input voltage by ana fixed transformer ratio toget theoutput is not so. Rather it is energy in joules that get transferred to create spark, and not simply voltage.</p>
The output voltage decays very rapidly. The capacitor that dumps the charge also has an impedance that is rpm (frequency) dependent. In other words, supplying a higher input voltage only provides a 'slightly' hotter spark.</p>
You said it yourself. The transformer has a certain ratio. Higher input voltage equals higher output voltage. Almost linear since the efficiency drops a bit (8% at 7v compared to 4.8v), see RC-EXL manual.